POV-Ray : Newsgroups : povray.general : constructing a geometry : Re: constructing a geometry Server Time
30 Jul 2024 12:28:13 EDT (-0400)
  Re: constructing a geometry  
From: stevenvh
Date: 5 Feb 2009 07:35:01
Message: <web.498adc8f39783190c0721a1d0@news.povray.org>
Nicolas George <nicolas$george@salle-s.org> wrote:
> "stevenvh"  wrote in message
> <web.498a917639783190c0721a1d0@news.povray.org>:
> > "Amir_ni" <nomail@nomail> wrote:
> >> distance between neighbor sphere is less than 1.4 times the radius of spheres, a
> >> cavity is formed in the center of cube. I want to make the shape of that cavity.
> > By the way, you already have a cavity when the distance is less than 1.73 times
> > the radius (sqrt(3)), because the distance from the center of a sphere to the
> > center of the cavity is sqrt(r^2 + r^2 + r^2). You have three dimensions here.
>
> In fact, if the radius is less than sqrt(2), there is no "cavity" at all,
> since the spheres on the diagonal of a face do not intersect.

Well, they do intersect, but they "cavity" isn't a closed volume, i.e. it's open
to the six sides of the cube.


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